Sami si m=C5=AF=C5=BEete naj=C3=ADt n=C3=A1hradu =
=C4=8Dl=C3=A1nkov=C3=BDch litinov=C3=BDch a ocelov=C3=BDch =
radi=C3=A1tor=C5=AF za=20
deskov=C3=A1 otopn=C3=A1 t=C4=9Blesa RADIK KLASIK - R
pan=20
Fitinka 08.03.2018 =20
Model RADIK KLASIK - R je deskov=C3=A9 otopn=C3=A9 =
t=C4=9Bleso v=20
proveden=C3=AD KLASIK upraven=C3=A9 pro rychlou n=C3=A1hradu =
=C4=8Dl=C3=A1nkov=C3=BDch litinov=C3=BDch nebo=20
ocelov=C3=BDch radi=C3=A1tor=C5=AF s p=C5=99ipojovac=C3=AD =
rozte=C4=8D=C3=AD 500 mm. V=C3=BD=C5=A1ka H =3D 554 mm=20
zaru=C4=8Duje jeho bezprobl=C3=A9movou mont=C3=A1=C5=BE =
na m=C3=ADsto star=C3=A9ho radi=C3=A1toru.=20
Umo=C5=BE=C5=88uje lev=C3=A9 nebo prav=C3=A9 bo=C4=8Dn=C3=AD =
p=C5=99ipojen=C3=AD na rozvod otopn=C3=A9=20
soustavy a konstrukc=C3=AD je ur=C4=8Deno pro otopn=C3=A9 soustavy s =
nucen=C3=BDm nebo samot=C3=AD=C5=BEn=C3=BDm=20
ob=C4=9Bhem. Ze zadn=C3=AD strany jsou p=C5=99iva=C5=99eny dv=C4=9B =
horn=C3=AD a doln=C3=AD p=C5=99=C3=ADchytky, otopn=C3=A1=20
t=C4=9Blesa o d=C3=A9lce 1800 mm a del=C5=A1=C3=AD maj=C3=AD =
nava=C5=99ena =C5=A1est p=C5=99=C3=ADchytek.
Identifikujte star=C3=BD =C4=8Dl=C3=A1nkov=C3=BD radi=C3=A1tor
ur=C4=8Dete materi=C3=A1l radi=C3=A1toru =
(litina/ocel) - pokud je povrch=20
Va=C5=A1eho =C4=8Dl=C3=A1nkov=C3=A9ho radi=C3=A1toru hrub=C3=BD, =
m=C3=A1te litinov=C3=BD radi=C3=A1tor
zm=C4=9B=C5=99te=20
v=C3=BD=C5=A1ku radi=C3=A1toru =
H
ov=C4=9B=C5=99te, jestli je=20
p=C5=99ipojovac=C3=AD rozte=C4=8D h =
opravdu 500 mm
zm=C4=9B=C5=99te=20
hloubku radi=C3=A1toru =
B
spo=C4=8D=C3=ADtejte=20
po=C4=8Det =C4=8Dl=C3=A1nk=C5=AF =
(=E2=80=9E=C5=BEeber=E2=80=9C)
Jak naj=C3=ADt n=C3=A1hradu v tabulce
Podle identifikace (viz. v=C3=BD=C5=A1e) vyhledejte v lev=C3=A9 =
=C4=8D=C3=A1sti tabulky p=C5=99=C3=ADslu=C5=A1n=C3=BD=20
sloupec, odpov=C3=ADdaj=C3=ADc=C3=AD typu star=C3=A9ho radi=C3=A1toru a =
najd=C4=9Bte =C5=99=C3=A1dek s p=C5=99=C3=ADslu=C5=A1n=C3=BDm =
po=C4=8Dtem=20
=C4=8Dl=C3=A1nk=C5=AF n (pokud nen=C3=AD v tabulce k dispozici =
p=C5=99esn=C3=BD po=C4=8Det, zvolte nejbli=C5=BE=C5=A1=C3=AD=20
vy=C5=A1=C5=A1=C3=AD). V =C5=99=C3=A1dku s =
p=C5=99=C3=ADslu=C5=A1n=C3=BDm po=C4=8Dtem =C4=8Dl=C3=A1nk=C5=AF v =
prav=C3=A9 (modr=C3=A9) =C4=8D=C3=A1sti tabulky vyberte=20
nejv=C3=ADce vyhovuj=C3=ADc=C3=AD d=C3=A9lku nov=C3=A9ho deskov=C3=A9ho =
t=C4=9Blesa L (ta je z=C3=A1visl=C3=A1 na typu=20
deskov=C3=A9ho t=C4=9Blesa). Po v=C3=BDb=C4=9Bru typu deskov=C3=A9ho =
t=C4=9Blesa prove=C4=8Fte je=C5=A1t=C4=9B kontrolu jeho=20
hloubky B, zda vyhovuje po=C5=BEadavk=C5=AFm.
![](3D"https://www.panfitinka.cz/storage/app/media/blog/sami%20si%20muzet=)
Tepeln=C3=A9 v=C3=BDkony =C4=8Dl=C3=A1nkov=C3=BDch =
radi=C3=A1tor=C5=AF
Pokud si nebudete s =
n=C4=9B=C4=8D=C3=ADm v=C4=9Bd=C4=9Bt rady, klidn=C4=9B n=C3=A1s=20
kontaktujte a my v=C3=A1m r=C3=A1di =
porad=C3=ADme!
Zp=C4=9Bt na blog